Find the value of x in 2x + 20 = 48
Find the maximum value and the minimum value of 3x4−8x3+12x2−48x+25 on the interval [0,3].
Find both the maximum value and the minimum value of
3x4 ā 8x3 + 12x2 ā 48x + 25 on the interval [0, 3]