Find the value of x 2x-13-6x-25-13-

The correct option is D 12 2x 1 3 6x 2 5 = 1 3 10x 5 3(6x 2) 15 = 1 3 10x 5 18x+6=5 8x=4 x= 1 2 ...

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Standard VII

Mathematics

Changing Scale (Including Flags)

Find the valu...

Question

Find the value of x

$\frac{2 x - 1}{3} - \frac{6 x - 2}{5} = \frac{1}{3}$ .

\frac{1}{2}

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\frac{2}{3}

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\frac{- 1}{2}

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\frac{- 2}{3}

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Solution

The correct option is D $\frac{- 1}{2}$
$\frac{2 x - 1}{3} - \frac{6 x - 2}{5} = \frac{1}{3}$

$\frac{10 x - 5 - 3 (6 x - 2)}{15} = \frac{1}{3}$

$10 x - 5 - 18 x + 6 = 5$

$- 8 x = 4$

$x = \frac{- 1}{2}$

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Similar questions

Q. If

x = 2 + 2^{1 / 3} 2^{2 / 3}

, find the value of

(x^{3} - 6 x^{2} + 6 x)

Q. If

x = 2^{1 / 3} + 2^{- 1 / 3}

prove that

2 x^{3} - 6 x - 5 = 0

x = 2 + 2^{1 / 3} + 2^{2 / 3}

. find the value of

x^{3} - 6 x^{2} + 6 x

Q. Solve

\frac{2 x - 1}{3} - \frac{6 x - 2}{5} = \frac{1}{3}

Solve :

$(i) \frac{1}{3} x - 6 = \frac{5}{2} (i i) \frac{2 x}{3} - \frac{3 x}{8} = \frac{7}{12} (i i i) (x + 2) (x + 3) + (x - 3) (x - 2) - 2 x (x + 1) = 0 (i v) \frac{1}{10} - \frac{7}{x} = 35 (v) 13 (x - 4) - 3 (x - 9) - 4 (x + 4) = 0 (v i) x + 7 - \frac{8 x}{3} = \frac{17 x}{6} - \frac{5 x}{8} (v i i) \frac{3 x - 2}{4} - \frac{2 x + 3}{3} = \frac{2}{3} - x (v i i i) \frac{x + 2}{6} - (\frac{11 - x}{3} - \frac{1}{4}) = \frac{3 x - 4}{12} (i x) \frac{2}{5 x} - \frac{5}{3 x} = \frac{1}{15} (x) \frac{x + 2}{3} - \frac{x + 1}{5} = \frac{x - 3}{4} - 1 (x i) \frac{3 x - 2}{3} + \frac{2 x + 3}{2} = x + \frac{7}{6} (x i i) x - \frac{x - 1}{2} = 1 - \frac{x - 2}{3} (x i i i) \frac{9 x + 7}{2} - (x - \frac{x - 2}{7}) = 36 (x i v) \frac{6 x + 1}{2} + 1 = \frac{7 x - 3}{3}$

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Find the value of x 2x−13−6x−25=13.

The correct option is D −122x−13−6x−25=1310x−5−3(6x−2)15=1310x−5−18x+6=5−8x=4x=−12

Find the value of x

$\frac{2 x - 1}{3} - \frac{6 x - 2}{5} = \frac{1}{3}$ .

The correct option is D $\frac{- 1}{2}$
$\frac{2 x - 1}{3} - \frac{6 x - 2}{5} = \frac{1}{3}$

$\frac{10 x - 5 - 3 (6 x - 2)}{15} = \frac{1}{3}$

$10 x - 5 - 18 x + 6 = 5$

$- 8 x = 4$

$x = \frac{- 1}{2}$