Question

Find the value of $x$ for the following cases

1)$\log x=\frac{1}{2}\left[\log \right(35.87)+\log (0.0514)-\log (0.0578\left)\right]$

2)$\log x=\frac{1}{2}[1.5548+2.7116-2.7619]$

Answer 1

$\left(1\right)\log x=\frac{1}{2}\left[\log \frac{35.87\times 0.0514}{0.0578}\right]$

$\log x=\log \left(5.64\right)$

$\therefore x=5.64$

$\left(2\right)\log x=\frac{3009}{4000}=\frac{3}{4}$ (nearly)

$\therefore x=2.1217$