Find the value of $x$ for the following equation.
$3 + x = 4 x - 3$ .

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Solution

Given: $3 + x = 4 x - 3$
Transposing $3$ to the R.H.S,
$x = 4 x - 3 - 3$
Transposing $4 x$ to the L.H.S,
$x - 4 x = - 3 - 3$
$- 3 x = - 6$
on isolating $x$ , we get
$x = \frac{- 6}{- 3}$
$x = 2$
Therefore, $2$ is the value of the $x$ for the given equation.

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