Find the value of x for which (8x+4), (6x-2) and (2x+7) are in A.P.
If a,b,c are in A.P
b=(a+c)/2
According to question 8x+4,6x-2,2x+7 are in A.P
6x-2=(8x+4+2x+7)/2
6x-2=10x+11/2
2(6x-2)=10x+11
12x-4=10x+11
12x-10x=11+4
2x=15
x=15/2=7.5