Question

Find the value of x for which
${\left(\frac{3}{4}\right)}^6\times {\left(\frac{16}{9}\right)}^5={\left(\frac{4}{3}\right)}^{x+2}$

Answer 1

$(\frac{3}{4}{)}^6\times (\frac{16}{9}{)}^5=(\frac{4}{3}{)}^{x+2}$

$(\frac{4}{3}{)}^{x+2}=(\frac{4}{3}{)}^{-6}(\frac{4}{3}{)}^{10}$

Comparing powers

$x+2=4⟹x=2$