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Question

Find the value of x for which
sinh1x+cosh1(x+2)=0

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Solution

sinh1x+cosh1(x+2)=0
cosh1x=log|x±x2+1|
sinh1x=log|x±x2+1|
So, cosh1(x+2)=log|x+2±(x+2)2+1|
Now, sinh1x+cosh1(x+2)
log(x+x2+1)+log(x+2+(x+2)2+1)
log(x+x2+1)+log(x+2+x2+4+4x+1)
log(x+x2+1)(x+2+x2+4+4x+1)
log(x+x2+1)(x+2+x2+4x.5)=0
[(x+2)+x2+4x+5](x+x2+1)

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