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Byju's Answer
Standard XII
Mathematics
Substitution Method to Remove Indeterminate Form
Find the valu...
Question
Find the value of
x
for which
sin
h
−
1
x
+
cos
h
−
1
(
x
+
2
)
=
0
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Solution
sinh
−
1
x
+
cosh
−
1
(
x
+
2
)
=
0
∵
cosh
−
1
x
=
log
|
x
±
√
x
2
+
1
|
sinh
−
1
x
=
log
|
x
±
√
x
2
+
1
|
So,
cosh
−
1
(
x
+
2
)
=
log
|
x
+
2
±
√
(
x
+
2
)
2
+
1
|
Now,
sinh
−
1
x
+
cosh
−
1
(
x
+
2
)
⇒
log
(
x
+
√
x
2
+
1
)
+
log
(
x
+
2
+
√
(
x
+
2
)
2
+
1
)
⇒
log
(
x
+
√
x
2
+
1
)
+
log
(
x
+
2
+
√
x
2
+
4
+
4
x
+
1
)
⇒
log
(
x
+
√
x
2
+
1
)
(
x
+
2
+
√
x
2
+
4
+
4
x
+
1
)
⇒
log
(
x
+
√
x
2
+
1
)
(
x
+
2
+
√
x
2
+
4
x
.5
)
=
0
⇒
[
(
x
+
2
)
+
√
x
2
+
4
x
+
5
]
(
x
+
√
x
2
+
1
)
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0
Similar questions
Q.
Find the value of
x
for which
sin
h
−
1
3
4
+
sin
h
−
1
x
=
sin
h
−
1
4
3
Q.
Prove that
cos
h
−
1
(
√
1
+
x
2
)
=
sin
h
−
1
x
=
tan
−
1
(
x
√
1
+
x
2
)
Q.
Find the value of
x
for which
sec
−
1
x
+
sin
−
1
x
=
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.
Q.
Differentiate
sin
h
−
1
x
with respect to
x
.
By writing
sin
h
−
1
x
as
1
×
sin
h
−
1
x
, use integration by parts to find
∫
2
1
sin
h
−
1
d
x
Q.
Prove the following :
(a)
cosh
2
x
−
sinh
2
x
=
1
(b)
sinh
2
x
=
2
sinh
x
cosh
x
(c)
cosh
2
x
=
cosh
2
x
+
sinh
2
x
(d)
tanh
2
x
=
1
−
sech
2
x
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