Find the value of $x$ for which the given expressions are equal.
$\frac{3 x + 2}{2}$ and $\frac{3 x}{4} - 2$

x = 5

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x = - 4

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x = 7

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x = - 9

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Solution

The correct option is B $x = - 4$
Given equations are
$\frac{3 x + 2}{2}$ and $\frac{3 x}{4} - 2$
It is said that both the equations are equal.
Therefore, $\frac{3 x + 2}{2} = \frac{3 x}{4} - 2$
$\Rightarrow 4 (3 x + 2) = 2 (3 x - 8)$
$\Rightarrow 12 x + 8 = 6 x - 16$
$\Rightarrow 6 x = - 24$
$\Rightarrow x = - 4$

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Find the value of x for which the value of the expressions $2x + 2$ and $\frac{2}{5} (x + 7)$ are equal.

\frac{3 x + 2}{2}

\frac{3}{4} x - 2

λ

(x^{2} + 3 x + 5)^{2} - (λ - 3) (x^{2} + 3 x + 4) (x^{2} + 3 x + 5) + (λ - 4) (x^{2} + 3 x + 4)^{2} = 0

3 x + \frac{2}{x} = 7

(9 x^{2} + \frac{4}{x^{2}})

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