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Question

Find the value of x for which the points Ax, 2, B-3, -4 and C7, -5 are collinear. [CBSE 2015]

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Solution

Let Ax1, y1=Ax, 2, Bx2, y2=B-3, -4 and Cx3, y3=C7, -5. So, the condition for three collinear points is
x1y2-y3+x2y3-y1+x3y1-y2=0x-4+5-3-5-2+72+4=0x+21+42=0x=-63
Hence, x = − 63.

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