Find the value of x from the equation xsin-6cos 2-4 - 2-6-3tan-4-cosec2-4cosec-6

The correct option is B 6 xsinπ/6cos ^2π/4= ^2π/6π/3tanπ/4/cosec^2π/4cosecπ/6 #160; #160;or #160; x×1/2×1/2= ( √(3) )^2× 2× 1/ ( √(2) )^2× 2 # ...

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Differentiation of Inverse Trigonometric Functions

Find the valu...

Question

Find the value of x from the equation $x sin \frac{π}{6} {cos}^{2} \frac{π}{4} = \frac{{cot}^{2} \frac{π}{6} sec \frac{π}{3} tan \frac{π}{4}}{c o s e c^{2} \frac{π}{4} c o s e c \frac{π}{6}}$

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x sin \frac{π}{6} {cos}^{2} \frac{π}{4} = \frac{{cot}^{2} \frac{π}{6} sec \frac{π}{3} tan \frac{π}{4}}{c o s e c^{2} \frac{π}{4} c o s e c \frac{π}{6}}

x sin \frac{π}{6} {cos}^{2} \frac{π}{4} = \frac{{cot}^{2} \frac{π}{6} sec \frac{π}{3} tan \frac{π}{4}}{cos {sec}^{2} \frac{π}{4} cos sec \frac{π}{6}}

x

x sin \frac{π}{6} {cos}^{2} \frac{π}{4} = \frac{{cot}^{3} \frac{π}{6} sec \frac{π}{6} tan \frac{π}{4}}{{csc}^{2} \frac{π}{4} csc \frac{π}{6}}

x

x sin \frac{π}{6} {cos}^{2} \frac{π}{4} = \frac{{cot}^{2} \frac{π}{6} sec \frac{π}{3} tan \frac{π}{4}}{c o {sec}^{2} \frac{π}{4} c o {sec} \frac{π}{6}}

4 sin \frac{π}{6} {sin}^{2} \frac{π}{3} + 3 cos \frac{π}{3} tan \frac{π}{4} + {cosec}^{2} \frac{π}{2} = 2 {sec}^{2} \frac{π}{4}

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