Question

Find the value of x if $[4^{2x}+10]÷2=37$.

Answer 1

We have, $[4^{2x}+10]÷2=37$

So, $4^{2x}+10=(37\times 2)$

$4^{2x}=74-10$

$4^{2x}=64$

$4^{2x}=(4{)}^3$

take log on both side we get

$\left(2x\right)log4=3log4$

$2x=3$

$x=\frac{3}{2}$