Find the value of x- if-12527-12527x - 5318

(12527)×(12527)^x = (53)^18 ⇒ (5^33^3) × (5^33^3)^x = (53)^18 ⇒ (53)^3 × (53)^3x = (53)^18 ⇒ 3 + 3x = 18 [Equating the powers of same base] 3x = 18 – 3 = 15 ...

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Byju's Answer

Standard VIII

Mathematics

Dividing Terms with the Same Exponent

Find the valu...

Question

Find the value of x, if:

$(\frac{125}{27}) \times (\frac{125}{27})^{x} = (\frac{5}{3})^{18}$

3^{5}

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5 \times 3 \times 5

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5^{3}

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Solution

The correct option is C 5
$(\frac{125}{27}) \times (\frac{125}{27})^{x} = (\frac{5}{3})^{18}$

$\Rightarrow (\frac{5^{3}}{3^{3}}) \times (\frac{5^{3}}{3^{3}})^{x} = (\frac{5}{3})^{18}$

$\Rightarrow (\frac{5}{3})^{3} \times (\frac{5}{3})^{3 x} = (\frac{5}{3})^{18}$

⇒ 3 + 3x = 18 [Equating the powers of same base]
3x = 18 – 3 = 15
x = 5

Suggest Corrections

Find the value of x, if: (12527)×(12527)x=(53)18

The correct option is C 5(12527)×(12527)x=(53)18 ⇒(5333)×(5333)x=(53)18 ⇒(53)3×(53)3x=(53)18 ⇒ 3 + 3x = 18 [Equating the powers of same base] 3x = 18 – 3 = 15 x = 5

Find the value of x, if:

$(\frac{125}{27}) \times (\frac{125}{27})^{x} = (\frac{5}{3})^{18}$