wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find the value of x, if

Given, 2345=x32x5

Open in App
Solution

Given, 2345=x32x5
On expanding both determinants, we get
2×54×3=5×x3×2x 1012=5x6x2=xx=2


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Algebra of Complex Numbers
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon