Find the value of x, if
Given, ∣∣∣2345∣∣∣=∣∣∣x32x5∣∣∣
Given, ∣∣∣2345∣∣∣=∣∣∣x32x5∣∣∣ On expanding both determinants, we get 2×5−4×3=5×x−3×2x⇒ 10−12=5x−6x⇒−2=−x⇒x=2
Find the value of k , if the matrix [2345]=[x32x5]
If ∣∣∣3x7−24∣∣∣=∣∣∣8764∣∣∣, find the value of x.