Question

Find the value of x,
If sin2x = sin60$°$ cos 30$°$ $-$ cos 60$°$ sin 30$°$

Answer 1

Given:
sin 2x = sin 60^o cos 30^o $-$ cos 60^o sin 30^o
$$\begin{gathered} \Rightarrow \sin 2x=\frac{\sqrt{3}}{2}\times \frac{\sqrt{3}}{2}-\frac{1}{2}\times \frac{1}{2} \\ \Rightarrow \sin 2x=\frac{3}{4}-\frac{1}{4} \\ \Rightarrow \sin 2x=\frac{2}{4} \\ \Rightarrow \sin 2x=\frac{1}{2} \\ \Rightarrow \sin 2x=\sin 30° \\ \Rightarrow 2x=30° \\ \Rightarrow x=15° \end{gathered}$$