Question

Find the value of x, If $\sqrt{\frac{1}{625}}=5^{-x}$

Answer 1

Given that, $\sqrt{\frac{1}{625}}=5^{(-x)}\sqrt{\frac{1}{{25}^2}}=\frac{1}{5^x}\frac{1}{25}=\frac{1}{5^x}\frac{1}{5^2}=\frac{1}{5^x}Comparingonbothsides,we,willgetx=2$