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(a+b)(a-b) Expansion and Visualisation

find the valu...

Question

find the value of x if y=1 when $y = (x + \sqrt{x^{2} - y^{2}}$ )

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Solution

$y = x + \sqrt{x^{2} - y^{2}} y = 1 ⟹ 1 = x + \sqrt{x^{2} - 1} 1 - x = \sqrt{x^{2} - 1} 1 + x^{2} - 2 x = x^{2} - 1 1 - 2 x = - 1 x = 1$

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