Find the value of x if $y = 3$ when $x^{2} + y^{2} = 25$

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Solution

$y = 3 x^{2} + y^{2} = 25 x^{2} + 3^{2} = 25 x^{2} + 9 = 25 x^{2} = 25 - 9 x^{2} = 16 x = \sqrt{16} x = \pm 4$

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If $(x^{2} - y^{2}) = 18$ and $(x - y) = 3$ , find the value of $x^{2} + y^{2} + 2 x y$ .

If (x²-y²) =18 and (x-y) =3, find the value of 16x²y²

x + y = 3, x y = 5

x^{2} + y^{2}

x = 3

y^{2} = x + 1

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