Find the value of $x$ in $25 : 81 :: 36 : x$

121

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100

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None of these

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Solution

The correct option is B 100
$25 : 81 :: 36 : x$

$\Rightarrow 5^{2} : 9^{2} :: 6^{2} : x$

Therefore, $\Rightarrow x = 10^{2}$

$\Rightarrow x = 100$

Suggest Corrections

Similar questions

x

(\frac{625}{81}) \times (\frac{125}{27})^{x} = (\frac{25}{9})^{8}

\frac{18}{81} \div \frac{36}{45} =

\frac{x}{18}

36 x^{2} + 25 y^{2} - 60 x y

\frac{x^{2}}{81} - \frac{y^{2}}{25} = 1

Find the value:

$\sqrt{81} + \sqrt{36}$ [2 MARKS]

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