Question

Find the value of $x$ in $\frac{4}{3}\times [x+\frac{1}{13}]=\frac{4}{3}\times \frac{8}{11}+\frac{4}{3}\times \frac{1}{13}.$

• A. $\frac{8}{11}$
• B. $\frac{11}{8}$
• C. $\frac{4}{3}$
• D. $\frac{1}{13}$

Answer 1

The correct option is A $\frac{8}{11}$

$\frac{4}{3}\times (x+\frac{1}{13})=\frac{4}{3}\times x+\frac{4}{3}\times \frac{1}{13}$

The distributive property over addition for rational numbers states that for any three rational numbers $a,b$ and $c:$

$a(b+c)=(a\times b)+(a\times c)$

$\frac{4}{3}\times \frac{8}{11}+\frac{4}{3}\times \frac{1}{13}=\frac{4}{3}\times (\frac{8}{11}\times \frac{1}{13})$