Question

Find the value of $x$ in each of the following diagram:

Answer 1

The total sum of angle $={180}^o$

$3x+x+x+{30}^o={180}^o$

$\therefore x={30}^o$

$\therefore \angle COF=3x={90}^o=\angle EOD$ ..... [alternate angle]

$\therefore \angle AOE={30}^o=\angle FOB$ ..... [alternate angle]

$\angle COA=\angle BOD={30}^o+{30}^o={60}^o$ ..... [alternate angle]

$\therefore$ Total sum $=\angle COF+\angle FOB+\angle BOD+\angle DOE+\angle AOE+\angle COA$

$={90}^o+{90}^o+{30}^o+{30}^o+{60}^o+{60}^o={360}^o$