Find the value of x in each of the following 2 7 -3 - 2 7 -11 - 2 7 7x

[ 27 ]^ 3 11= [ 27 ]^7x [ 27 ]^ 14= [ 27 ]^7x #160; 7x= 14 #160; x= 2 ...

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Question

Find the value of $x$ in each of the following ${(\frac{2}{7})}^{- 3} \times {(\frac{2}{7})}^{- 11} = {(\frac{2}{7})}^{7 x}$

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x

1 \frac{2}{3} \div \frac{2}{7} \times \frac{x}{7} = 1 \frac{1}{4} \times \frac{2}{3} \div \frac{1}{6}

x

{(\frac{2}{7})}^{- 3} \times {(\frac{2}{7})}^{- 11} = {(\frac{2}{7})}^{5 x + 2}

x

7^{2} + 3^{4} - 4^{3} = x - 11^{2}

(i) \frac{5 + 2 \sqrt{3}}{7 + 4 \sqrt{3}} = a - 6 \sqrt{3}

(i i) \frac{3 - \sqrt{5}}{3 + 2 \sqrt{5}} = a \sqrt{5} - \frac{19}{11}

(i i i) \frac{\sqrt{2} + \sqrt{3}}{3 \sqrt{2} - 2 \sqrt{3}} = 2 - b \sqrt{6}

(i v) \frac{7 + \sqrt{5}}{7 - \sqrt{5}} - \frac{7 - \sqrt{5}}{7 + \sqrt{5}} = a + \frac{7}{11} \sqrt{5} b

Find the value of $lim x \to \infty \frac{2 x^{2} - 3 x + 11}{7 x^{2} + 8 x + 15}$

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