Find the value of x in kx - a - mx - b-b-a-k-ma-b-k-mk-m-a-bm-k-a-b

The correct option is A b a/k mGiven equation is: kx +a = mx + b ⇒ kx – mx = b –a [mx is transposed as –mx, a is transposed as –a] ⇒ x(k – m) = b – a ⇒ x=b a/k ...

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Byju's Answer

Standard VII

Mathematics

Variable and Constants

Find the valu...

Question

Find the value of $x$ in $k x + a = m x + b$ .

\frac{b - a}{k - m}

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\frac{a - b}{k - m}

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\frac{k - m}{a - b}

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\frac{m - k}{a - b}

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Solution

The correct option is A $\frac{b - a}{k - m}$
Given equation is: $k x + a = m x + b$
$\Rightarrow$ $k x - m x = b - a$
[mx is transposed as –mx, a is transposed as –a]
$\Rightarrow$ $x (k - m) = b - a$
$\Rightarrow x = \frac{b - a}{k - m}$

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, then value of

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k x + a = m x + b

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Find the value of x in kx+a=mx+b.

The correct option is A b−ak−mGiven equation is: kx+a=mx+b ⇒ kx–mx=b–a [mx is transposed as –mx, a is transposed as –a] ⇒ x(k–m)=b–a ⇒x=b−ak−m

Find the value of $x$ in $k x + a = m x + b$ .

The correct option is A $\frac{b - a}{k - m}$
Given equation is: $k x + a = m x + b$
$\Rightarrow$ $k x - m x = b - a$
[mx is transposed as –mx, a is transposed as –a]
$\Rightarrow$ $x (k - m) = b - a$
$\Rightarrow x = \frac{b - a}{k - m}$