Find the value of x in the diagram below.
20
3
9
12
We have BA × BC = BE × BD
3×15=5×x
x=455
x=9
C(n,12) = C(n,8) N = ?
(−7)+(−9)+12+(−16)=?(a) −20(b) 20(c) −12(d) none of these
Number of σsp2−sp2 bonds pre3sent in a molecule of x in the process C6H6H2/Ni−−−−→X is