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Byju's Answer
Standard XII
Mathematics
Polynomial Functions
Find the valu...
Question
Find the value of
x
in the equation
∣
∣ ∣
∣
1
4
20
1
−
2
5
1
2
x
5
x
2
∣
∣ ∣
∣
=
0
A
−
1
,
2
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B
1
,
0
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C
2
,
0
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D
1
,
2
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Solution
The correct option is
A
−
1
,
2
∣
∣ ∣
∣
1
4
20
1
−
2
5
1
2
x
5
x
2
∣
∣ ∣
∣
=
0
Applying
R
2
→
R
2
−
R
1
,
R
3
→
R
3
−
R
1
⇒
∣
∣ ∣
∣
1
4
20
0
−
6
−
15
0
2
x
−
4
5
x
2
−
20
∣
∣ ∣
∣
=
0
⇒
−
6
(
5
x
2
−
20
)
+
15
(
2
x
−
4
)
=
0
⇒
−
30
x
2
+
120
+
30
x
−
60
=
0
⇒
30
x
2
−
30
x
−
60
=
0
⇒
x
2
−
x
−
2
=
0
⇒
(
x
−
2
)
(
x
+
1
)
=
0
⇒
x
=
−
1
,
2
Suggest Corrections
0
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