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Question

Find the value of x in the equation ∣ ∣142012512x5x2∣ ∣=0

A
1,2
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B
1,0
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C
2,0
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D
1,2
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Solution

The correct option is A 1,2
∣ ∣142012512x5x2∣ ∣=0
Applying R2R2R1,R3R3R1
∣ ∣1420061502x45x220∣ ∣=0

6(5x220)+15(2x4)=0

30x2+120+30x60=0

30x230x60=0

x2x2=0

(x2)(x+1)=0

x=1,2

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