wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find the value of x in the equation ∣ ∣142012512x5x2∣ ∣=0

A
1,2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
1,0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2,0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
1,2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 1,2
∣ ∣142012512x5x2∣ ∣=0
Applying R2R2R1,R3R3R1
∣ ∣1420061502x45x220∣ ∣=0

6(5x220)+15(2x4)=0

30x2+120+30x60=0

30x230x60=0

x2x2=0

(x2)(x+1)=0

x=1,2

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Some Functions and Their Graphs
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon