Question

Find the value of $x$ in the following:
$2\sin 3x=\sqrt{3}$

Answer 1

Given,

$2\sin 3x=\sqrt{3}$

$\sin 3x=\frac{\sqrt{3}}{2}$

we know that,

$\sin {60}^{\circ }=\frac{\sqrt{3}}{2}$

$\therefore \sin 3x=\sin {60}^{\circ }$

$3x={60}^{\circ }$

$x=\frac{{60}^{\circ }}{3}$

$x={20}^{\circ }$