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Question

Find the value of x in the following case:

1112=121x


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Solution

Finding the value of x:

We know, in two equivalent fractions, the product of the numerator of the first fraction and the denominator of the second fraction is equal to the product of the numerator of the second fraction and the denominator of the first fraction.

Given equivalent fractions:

1112=121x

11×x=121×12(ApplyingCross-Multiplication)x=121×1211x=132

Hence, the value of x is 132.


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