Find the value of x in the following figure.

$60^{\circ}$

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$110^{\circ}$

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$70^{\circ}$

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$130^{\circ}$

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Solution

The correct option is D
$130^{\circ}$

Sum of the angles should be equal to $360^{\circ}$ .
$100^{\circ} + 56^{\circ} + 74^{\circ} + x^{\circ} = 360^{\circ}$
$230^{\circ} + x^{\circ} = 360^{\circ}$
$\Rightarrow x^{\circ} = 360^{\circ} - 230^{\circ} = 130^{\circ}$

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Question 17

In the given figure, PA|| BC|| DT and AB|| DC. Then, the values of a and b

(a) $60^{\circ}, 120^{\circ}$
(b) $50^{\circ}, 130^{\circ}$
(c) $70^{\circ}, 110^{\circ}$
(d) $80^{\circ}, 100^{\circ}$

Find the value of y, when x = 60 $^{0}$ in the figure below.

Q. In the given figure, AB || CD. If ∠ABO = 130° and ∠OCD = 110, then ∠BOC = ?
(a) 50°
(b) 60°
(c) 70°
(d) 80°

Q. In the given figure, ∠OAB = 110° and ∠BCD = 130° then ∠ABC is equal to

(a) 40°
(b) 50°
(c) 60°
(d) 70°

The median of the following data is:

$\begin{matrix} I Q & 60 - 70 & 70 - 80 & 80 - 90 & 90 - 100 & 100 - 110 & 110 - 120 & 120 - 130 N o . o f p u p i l s & 2 & 3 & 5 & 16 & 14 & 13 & 7 \end{matrix}$

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Find the value of x in the following figure.

The correct option is D 130∘ Sum of the angles should be equal to 360∘. 100∘+56∘+74∘+x∘=360∘ 230∘+x∘=360∘ ⇒x∘=360∘−230∘=130∘

The correct option is D
$130^{\circ}$

Sum of the angles should be equal to $360^{\circ}$ .
$100^{\circ} + 56^{\circ} + 74^{\circ} + x^{\circ} = 360^{\circ}$
$230^{\circ} + x^{\circ} = 360^{\circ}$
$\Rightarrow x^{\circ} = 360^{\circ} - 230^{\circ} = 130^{\circ}$