Find the value of x in the following triangle.

60^{\circ}

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40^{\circ}

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120^{\circ}

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80^{\circ}

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Solution

The correct option is A $60^{\circ}$
All the three interior angles of triangle are also equal to x (Vertically opposite angles)
$x + x + x = 180^{\circ}$ (Angle sum property)
$3 x = 180^{\circ}$
$x = 60^{\circ}$

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Similar questions

50

x

y

Class-interval	$0 - 20$	$20 - 40$	$40 - 60$	$60 - 80$	$80 - 100$	Total
Frequency	$17$	$x$	$32$	$y$	$19$	$120$

Class interval	$0 - 20$	$20 - 40$	$40 - 60$	$60 - 80$	$80 - 100$	$100 - 120$	$120 - 140$
Frequency	$6$	$8$	$10$	$12$	$6$	$5$	$3$

∠ A C D = 120^{\circ}

∠ B C D

Class interval	$0 - 20$	$20 - 40$	$40 - 60$	$60 - 80$	$80 - 100$	$100 - 120$	$120 - 140$
Frequency	$4$	$15$	$23$	$12$	$16$	$8$	$2$

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