Find the value of $^{'} x^{'}$ in the series: $144, 169, x, 225, 256, 289$ .

190

No worries! We‘ve got your back. Try BYJU‘S free classes today!

192

No worries! We‘ve got your back. Try BYJU‘S free classes today!

196

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

195

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 196
The series is a perfect square in increasing order of $12, 13, 14, 15...$
So, the value of $x$ is $196$ .

Suggest Corrections

Similar questions

Ω

\sqrt{2 N + 17} = X,

(- π, π) f o r f (x) = x cos x

a_{0}

Join BYJU'S Learning Program