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Question 163
Find the value of x in the trapezium ABCD given below


Solution

Given, a trapezium ABCD in which A=(x20),D=(x+40)
Since, in a trapezium, the angles between the parallel lines are supplementary,
(x20)+(x+40)=180x20+x+40=1802x+20=1802x=(18020)=160x=80

Mathematics
NCERT Exemplar
Standard VIII

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