Find the value of $x^{o}$ .

100^{o}

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120^{o}

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110^{o}

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130^{o}

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Solution

The correct option is A $100^{o}$

An exterior angle of a triangle is equal to the sum of its interior opposite angles.

So,
$∠ B A C + ∠ A B C = x 50^{o} + 60^{o} = x x = 110^{o}$

So, the value of
$x = 110^{o}$ .

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