Question

Find the value of $x^o$.

• A. ${100}^o$
• B. ${120}^o$
• C. ${110}^o$
• D. ${130}^o$

Answer 1

The correct option is A ${100}^o$



An exterior angle of a triangle is equal to the sum of its interior opposite angles.

So,
$\angle BAC+\angle ABC=x{50}^o+{60}^o=xx={110}^o$

So, the value of
$x={110}^o$.