Question

Find the value of $x^o$ and $y^o$ from the given figures.

Answer 1

From the given figure,

$\angle ABC=\angle BCD=x={42}^o$ [Alternate interior angles]

As, $\angle BED={82}^o$

$\angle DEC={180}^o-{82}^o={98}^o$ [Adjacent Angle]

Consider $△CED$,

By Angle Sum Property,

$\angle C+\angle CED+\angle D={180}^o$

$\Rightarrow y={180}^o-{98}^o-{42}^o={40}^o$