Question

Find the value of x of y using the information shown in the figure. Find the measure of $\angle ABD$ and $\angle ACD$

Answer 1

Given that

$\angle CBD={60}^{0}and\angle ACB={50}^0$

And given $AB=AC$ and $BD=DC$

To find the value of $xandy$

Solution: In $\Delta ABC,$

$x={50}^0$ (Isosceles triangle theorem)

$y={60}^0$ (Isosceles triangle theorem)

We know that,

$\angle ABD=\angle ABC+\angle CBD$

$=x+{60}^0$

$={50}^0+{60}^0$

$\angle ABD={110}^0$

And now,

$\angle ACD=\angle ACB+\angle BCD$

$={50}^0+y$

$={50}^0+{60}^0$

$={110}^0$