Find the value of x so that-1.(9/4) exponent 3*(8/9)exponent 3=2 exponent 6x

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Solution

Dear Student,

$I f t h e e x a c t q u e s t i o n i s 1 \times {(\frac{9}{4})}^{3} \times {(\frac{8}{9})}^{3} = 2^{6 x} t h e n b e l o w i s t h e s o l u t i o n 1 \times {(\frac{9}{4})}^{3} \times {(\frac{8}{9})}^{3} = 2^{6 x} \sin c e w e k n o w a^{m} \times b^{m} = {(a \times b)}^{m} \Rightarrow {(\frac{9}{4} \times \frac{8}{9})}^{3} = 2^{6 x} \Rightarrow {(\frac{8}{4})}^{3} = 2^{6 x} \Rightarrow {(2)}^{3} = 2^{6 x} S i n c e t h e b a s e i s s a m e h e n c e e q u a t i n g t h e e x p o n a n t s t h e r e f o r e 6 x = 3 x = \frac{3}{6} x = \frac{1}{2}$
Regards,

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