Find the value of x so that 342x-1-343-3-

(34)^2x+1 =[(34)^3]^3 (34)^2x+1= (34) ^3 × 3 since base are same on equality power, we get 2x+1=9 x=4 ...

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Standard IX

Mathematics

Product Law

Find the valu...

Question

Find the value of x so that ${(\frac{3}{4})}^{2 x + 1} = {[{(\frac{3}{4})}^{3}]}^{3}$ .

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Solution

${(\frac{3}{4})}^{2 x + 1} = {[{(\frac{3}{4})}^{3}]}^{3}$
${(\frac{3}{4})}^{2 x + 1} = {(\frac{3}{4})}^{3 \times 3}$
since base are same on equality power, we get
$2 x + 1 = 9$
$x = 4$

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Find the value of x so that (34)2x+1=[(34)3]3.

(34)2x+1=[(34)3]3(34)2x+1=(34)3×3since base are same on equality power, we get2x+1=9x=4

Find the value of x so that ${(\frac{3}{4})}^{2 x + 1} = {[{(\frac{3}{4})}^{3}]}^{3}$ .

${(\frac{3}{4})}^{2 x + 1} = {[{(\frac{3}{4})}^{3}]}^{3}$
${(\frac{3}{4})}^{2 x + 1} = {(\frac{3}{4})}^{3 \times 3}$
since base are same on equality power, we get
$2 x + 1 = 9$
$x = 4$