Question

Find the value of '$x$' such that
${(-2)}^{x+1}\times {(-2)}^7={(-2)}^{12}$

Answer 1

${(-2)}^{x+1}\times {(-2)}^7={(-2)}^{12}$
${(-2)}^{x+1+7}={(-2)}^{12}$
${(-2)}^{x+8}={(-2)}^{12}$
As bases are equal, hence
$x+8=12$
$\therefore$ $x=12-8=4$