Find the value of x such that 12-4x-7 and 21-3x-6 form the opposite sides of a sqare

The correct option is B 35/24 Given that 124x 7 and 213x 6 are opposite sides of the square.Thus, 124x 7 = 213x 6 36x 72 = ...

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Standard VII

Mathematics

(a + b)^2 Expansion and Visualisation

Find the valu...

Question

Find the value of x such that $\frac{12}{4 x - 7}$ and $\frac{21}{3 x - 6}$ form the opposite sides of a sqare

\frac{3}{16}

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\frac{35}{24}

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\frac{25}{16}

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\frac{25}{6}

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Solution

The correct option is B $\frac{35}{24}$
Given that $\frac{12}{4 x - 7}$ and $\frac{21}{3 x - 6}$ are opposite sides of the square.
Thus, $\frac{12}{4 x - 7} = \frac{21}{3 x - 6}$
$36 x - 72 = 84 x - 142$
$70 = 48 x$
$x = \frac{70}{48} = \frac{35}{24}$

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Similar questions

Q. Find x such that:

(i)

\frac{- 1}{5} = \frac{8}{x}

(ii)

\frac{7}{- 3} = \frac{x}{6}

(iii)

\frac{3}{5} = \frac{x}{- 25}

(iv)

\frac{13}{6} = \frac{- 65}{x}

(v)

\frac{16}{x} = - 4

(vi)

\frac{- 48}{x} = 2

Using the method of completion of squares find one of the roots of the equation $2 x^{2} - 7 x + 3 = 0$ . Also, find the equation obtained after completion of the square.

Find each of the following products :

(i) $\frac{3}{5} \times \frac{- 7}{8}$ (ii) $\frac{- 9}{2} \times \frac{5}{4}$ (iii) $\frac{- 6}{11} \times \frac{- 5}{3}$

(iv) $\frac{- 2}{3} \times \frac{6}{7}$ (v) $\frac{- 12}{5} \times \frac{10}{- 3}$ (vi) $\frac{25}{- 9} \times \frac{3}{- 10}$

(vii) $\frac{5}{- 18} \times \frac{- 9}{20}$ (viii) $\frac{- 13}{15} \times \frac{- 25}{26}$ (ix) $\frac{16}{- 21} \times \frac{14}{5}$

(x) $\frac{- 7}{6} \times 24$ (xi) $\frac{7}{24} \times (- 48)$ (xii) $\frac{- 13}{5} \times (- 10)$

2 \frac{5}{8} + \frac{7}{16} =

3 \frac{x}{16}

. Find x.

Q. Find the median from the following data:

Class	1-5	6-10	11-15	16-20	21-25	26-30	31-35	35-40	41-45
Frequency	7	10	16	32	24	16	11	5	2

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Find the value of x such that 124x−7 and 213x−6 form the opposite sides of a sqare

The correct option is B 3524Given that 124x−7 and 213x−6 are opposite sides of the square.Thus, 124x−7=213x−636x−72=84x−14270=48xx=7048=3524

Find the value of x such that $\frac{12}{4 x - 7}$ and $\frac{21}{3 x - 6}$ form the opposite sides of a sqare

The correct option is B $\frac{35}{24}$
Given that $\frac{12}{4 x - 7}$ and $\frac{21}{3 x - 6}$ are opposite sides of the square.
Thus, $\frac{12}{4 x - 7} = \frac{21}{3 x - 6}$
$36 x - 72 = 84 x - 142$
$70 = 48 x$
$x = \frac{70}{48} = \frac{35}{24}$