Find the value of x such that points (0, 3), (x, 9) and (12, 15) are collinear.

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Solution

The correct option is A
6

The given point (x, 9) is the midpoint of the line joining the two points because:
$9 = \frac{3 + 15}{2}$
$x = \frac{0 + 12}{2}$
$x = 6$

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