Find the value of x when 42x-132-

The correct option is A 5/4 4^2x=1/32⇒ ( 2^2 )^2x=1/2^5 ⇒ 2^4x=2^ 5 ⇒ 4x= 5 ⇒ x= 5/4 ...

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Product Law

Find the valu...

Question

Find the value of $x$ when $4^{2 x} = \frac{1}{32}$ .

- \frac{5}{4}

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\frac{4}{5}

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\frac{3}{5}

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\frac{5}{3}

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4^{2 x} = \frac{1}{32}

- \frac{5}{4}

If $4^{2 x} = \frac{1}{32}, t h e n x i s$

x

{(\frac{4}{3})}^{- 4} \times {(\frac{4}{3})}^{- 5} = {(\frac{4}{3})}^{- 3 x}

7^{x} \div 7^{3} = 7^{5}

4^{2 x + 1} \div 16 = 64

x = \frac{5}{(2!) 3} + \frac{5 \cdot 7}{(3!) 3^{2}} + \frac{5 \cdot 7 \cdot 9}{(4!) 3^{3}} + . . . . .

x^{2} + 4 x

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