Find the value of x which satisfies the given equation. 3x+5=17
x=44
x=4
x=12
x=43
Given, 3x+5=17. Subtracting 5 from LHS and RHS, we get 3x+5−5=17−5 3x=12 Dividing both sides by 3, we get 3x3=123x=4