Question

Find the value of $x$ which satisfies $x^2-8x+13=0$

• A. $-4\pm \sqrt{3}$
• B. $-4\pm 2\sqrt{3}$
• C. $4\pm \sqrt{3}$
• D. $4\pm 3\sqrt{2}$
• E. $4\pm 2\sqrt{2}$

Answer 1

Answer: (C)

$4\pm \sqrt{3}$

Given equation is $x^2-8x+13=0$
$a=1,b=-8$ and $c=13$

By using quadratic formula:
$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\therefore x=\frac{(8\pm \sqrt{64-52})}{2}$

$=\frac{(8\pm \sqrt{12})}{2}$

$=\frac{(8\pm 2\sqrt{3})}{2}$

$=4\pm \sqrt{3}$