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Question

Find the value of x which satisfy this inequality:
π2sin1(1x21+x2) π3

A
12
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B
13
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C
both A and B
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D
None of these
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Solution

The correct option is B 13
We have π3π2sin1(1x21+x2)π3

5π6sin1(1x21+x2)π6

5π6sin1(1x21+x2)π6
sin1(1x21+x2)=π6,5π6
1x21+x2=sin(π6)
1x21+x2=12
22x2=1+x2

x2=13

x=±13

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