$F i n d t h e v a l u e o f x : (x + 1) (x + 2) = (x - 3) (x - 4)$

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Solution

The correct option is A
1

$x (x + 2) + 1 (x + 2) = x (x - 4) - 3 (x - 4) \Rightarrow x^{2} + 2 x + x + 2 = x^{2} - 4 x - 3 x + 12 \Rightarrow 3 x + 2 = - 7 x + 12 \Rightarrow 10 x = 10 \Rightarrow x = 1$

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Similar questions

[\begin{matrix} x + 1 & x - 1 x - 3 & x + 2 \end{matrix}] = [\begin{matrix} 4 & - 1 1 & 3 \end{matrix}]

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∣ ∣ ∣ \begin{matrix} x + 1 & x - 1 x - 3 & x + 2 \end{matrix} ∣ ∣ ∣ = ∣ ∣ ∣ \begin{matrix} 4 & - 1 1 & 3 \end{matrix} ∣ ∣ ∣

x,

∣ ∣ ∣ \begin{matrix} x + 1 & x - 1 x - 3 & x + 2 \end{matrix} ∣ ∣ ∣ = ∣ ∣ ∣ \begin{matrix} 4 & - 1 1 & 3 \end{matrix} ∣ ∣ ∣

|\begin{matrix} x + 1 & x - 1 \\ x - 3 & x + 2 \end{matrix}| = |\begin{matrix} 4 & - 1 \\ 1 & 3 \end{matrix}|

|\begin{matrix} 2 & 4 \\ 5 & 1 \end{matrix}| = |\begin{matrix} 2 x & 4 \\ 6 & x \end{matrix}|

|\begin{matrix} 2 & 3 \\ 4 & 5 \end{matrix}| = |\begin{matrix} x & 3 \\ 2 x & 5 \end{matrix}|

|\begin{matrix} 3 & x \\ x & 1 \end{matrix}| = |\begin{matrix} 3 & 2 \\ 4 & 1 \end{matrix}|

|\begin{matrix} 3 x & 7 \\ 2 & 4 \end{matrix}| = 10

|\begin{matrix} x + 1 & x - 1 \\ x - 3 & x + 2 \end{matrix}| = |\begin{matrix} 4 & - 1 \\ 1 & 3 \end{matrix}|

|\begin{matrix} 2 x & 5 \\ 8 & x \end{matrix}| = |\begin{matrix} 6 & 5 \\ 8 & 3 \end{matrix}|

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