Find the value of $x$
$x^{2} + 16 x - 36 = 0$

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Solution

$x^{2} + 16 x - 36 = 0$
splitting middle portion into two parts
$x^{2} + 18 x - 2 x - 36 = 0$
$x (x + 18) - 2 (x + 18) = 0$
$(x + 18) (x - 2) = 0$
$x = 2, - 18$

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