Find the value of $x$ :
$x^{2} + x - 182 = 0$

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Solution

$x^{2} + x - 182 = 0$
$\Rightarrow$ $x^{2} + 14 x - 13 x - 182 = 0$
$\Rightarrow$ $x (x + 14) - 13 (x + 14) = 0$
$\Rightarrow$ $(x + 14) (x - 13) = 0$
$\Rightarrow$ $x + 14 = 0$ and $x - 13 = 0$
$∴$ $x = - 14, 13$

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