Question

Find the value of $x$ :
$x^2+x-182=0$

Answer 1

$x^2+x-182=0$

$\Rightarrow$ $x^2+14x-13x-182=0$

$\Rightarrow$ $x(x+14)-13(x+14)=0$

$\Rightarrow$ $(x+14)(x-13)=0$

$\Rightarrow$ $x+14=0$ and $x-13=0$

$\therefore$ $x=-14,13$