Question

Find the value of $x$ :-
$x-[2x-\frac{3x-4}{7}]=\frac{4x-27}{3}-3$

Answer 1

$x-[2x-\frac{3x-4}{7}]=\frac{4x-27}{3}-3$

$\Rightarrow x-\left[\frac{14x-3x+4}{7}\right]=\frac{4x-27-9}{3}$

$\Rightarrow x-\frac{11x+4}{7}=\frac{4x-36}{3}$

$\Rightarrow \frac{7x-11x-4}{7}=\frac{4x-36}{3}$

$\Rightarrow \frac{-4x-4}{7}=\frac{4x-36}{3}$

$\Rightarrow \frac{-4(x+1)}{7}=\frac{4(x-9)}{3}$

$\Rightarrow \frac{(-x-1)}{7}=\frac{(x-9)}{3}$

$\Rightarrow -3x-3=7x-63$

$\Rightarrow -3x-7x=-63+3$

$\Rightarrow -10x=-60$

$\Rightarrow x=\frac{-60}{-10}=6$

$\therefore x=6$