Find the value of x-y2 x-y-x-2 yx-y when x-2 and y-1A- 18B- 17C- 19D- 21

The correct option is C 19 Given (x + y)(2x + y) + (x + 2y)(x y) Substitute nbsp; x = 2 and y = 1 in the above expression. = nbsp;( 2 nbsp;+( 1))(2( ...

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Standard VI

Mathematics

Expressing Relations in Multiplication and Addition

Find the valu...

Question

Find the value of $(x + y) (2 x + y) + (x + 2 y) (x - y)$ when $x = - 2$ and $y = - 1$

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Solution

The correct option is C
19

Given $(x + y) (2 x + y) + (x + 2 y) (x - y)$

Substitute $x = - 2$ and $y = - 1$ in the above expression.

= $(- 2 + (- 1)) (2 (- 2) + (- 1)) + (- 2 + 2 (- 1)) (- 2 - (- 1))$

= $(- 2 - 1) (- 4 - 1) + (- 2 - 2) (- 2 + 1)$

= $(- 3) (- 5) + (- 4) (- 1)$

= $15 + 4$

= $19$

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Find the value of (x+y)(2x+y)+(x+2y)(x−y) when x=−2 and y=−1

The correct option is C 19 Given (x+y)(2x+y)+(x+2y)(x−y) Substitute x=−2 and y=−1 in the above expression. = (−2+(−1))(2(−2)+(−1))+(−2+2(−1))(−2−(−1)) = (−2−1)(−4−1)+(−2−2)(−2+1) = (−3)(−5)+(−4)(−1) = 15+4 = 19

Find the value of $(x + y) (2 x + y) + (x + 2 y) (x - y)$ when $x = - 2$ and $y = - 1$