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Question

Find the value of (x+y)4 using Pascal's triangle.

A
x4+3x3y+5x2y2+3xy3+y4
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B
x4+2x3y+6x2y2+2xy3+y4
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C
x4+4x3y+6x2y2+4xy3+y4
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D
x4+4x3y+4x2y2+4xy3+y4
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Solution

The correct option is C x4+4x3y+6x2y2+4xy3+y4
We know that the value of (x+y)n for any value of n (>0) can be obtained using the Pascal's triangle.

The coefficients for the expression (x+y)n are as follows:

Binomial theorem - Wikipedia
(x+y)4=1x4y0+4x3y1+6x2y2+4x1y3+1x0y4 =x4+4x3y+6x2y2+4xy3+y4

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